Friday, 12 October 2012

Solved Question of Exercise 10.1 of Class 11th Q. No. 3

Q. No. 3 :     


 Find the distance between P(x1, y1) and Q(x2, y2) when
  1.      PQ is parallel to y-axis.
  2.      PQ is parallel to x-axis.               

Sol : 

1.
               When PQ is parallel to y-axis, every point on this line has the same abscissa.
                Let      X2 = X1
 
 
 


      
          The points P and Q are P(x1, y1) and Q(x2, y2)
 
     Therefore              PQ = ! Y2 - Y1 !
 
 
2.
 
              When PQ is parallel to x-axis. Every point on the line has the same ordinate. 
              
                Let   Y2 = Y1
 
 

 
 
Therefore          The Q Coordinates of points P and Q are (x1, y1) , (x2, y2)
 
               Therefore                PQ = ! X2 - X1 !



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