Thursday 25 April 2013

Conditions for Maxima and Minima

Conditions for Maxima and Minima


If y = f(x), then for maximum or minimum value of y for a value of x the first differential coefficient of y w.r.t. x should be zero.
i.e.
dy/dx = 0.
Find the value of x from here.

Now, find the 2nd derivative of y w.r.t. x i.e. d2y/dx2 and put the value of x.

1. If the value of d2y/dx2 is negative, then y is maximum for given value of x.

2. If the value of d2y/dx2 is positive, then y is minimum for a given value of x.

Formulae of Differentiation

Fundamental Formulae of Differentiation



Derivatives of Trigonometrical Functions



Derivatives of Logarithmic and Exponential Functions


Wednesday 10 April 2013

Solution of Triangles


                        Solution of Triangles


In a triangle, there are six elements or parts, three sides and three angles. From plane geometry, we know that if three of the elements are given, at least one of which must be a side, then the other three elements can be uniquely determined. If only three angles are given, then no unique solution of the triangle is possible but unlimited number of equiangular triangles can be found, the three angles of which are equal to the three given angles. The method of determining the unknown parts from the known parts, is called solving a triangle.

Again, it is evident that the three given parts cannot be independent or arbitrary. For instance, in a triangle, two of its angles can not be obtuse or the sum of any two sides cannot be less than or equal to the third.
A triangle is called a right-angled triangle or right triangle if one of its angle is a right angle otherwise, the triangle is called an oblique triangle. We start with the solution of right-angled triangles and the solution of oblique triangle will follow.
Whenever found convenient, logarithms should be used.

Solution of right-angled triangle

In this case, one angle is equal to 90 degree. If any two (at least one of which is a side) of the remaining five parts are given then the other unknown parts of the triangle can be determined.
If ABC be a right-angled triangle, where C = 90 degree then for solving the triangle, we have the following relations:
C = 90 degree, A B = 90 degree,
c^2 = a^2 b^2.
sin A =a/c, sin B = b/c, tan A =a/b = cot B.

                     Solution of oblique triangles

The various cases that may arise in solving oblique triangles are the following:
a) Three angles are given:
In this case, no definite values of the sides can be found but the ratio of the sides is determined. 

b) Three sides are given
In this case, unique solution of the triangle is possible.

c) Two sides and the included angle between them are given
In this case, triangle is unique.

d) Two angles and one side are given
The triangle is also unique in this case.

e) Two sides and the angle opposite to one of them are given
In this case, no triangle or more than one triangle is possible (ambiguous case).

General Remarks
Different trigonometric formulae may be used in different cases. The same problem may also be solved by using different formulae and by different methods. If no additional data are given in the problem, the formula, which is most suitable, should be chosen. If additional data are supplied, then the formula, which will fit in with the given data, must be selected. It has been found that for logarithmic computations tangent formula is most suitable.

The difference in the value of tan x is larger than that of tabular sin x or cos x. Hence, a small error in the tabular tangent will not affect the value of x so much as in the case tabular sine or cosine. In fact, 4-figure logarithmic tangent table gives more accurate result than even the 7-figure logarithmic sine or cosine table.

Note: If the angle is determined by the sine formula, then ambiguity may arise in the result. For example, if sin A = 1/2, then A = 30 degree or 150 degree, both are equally possible for being an angle of a triangle. This difficulty will not arise, when the angle is determined by cosine or tangent formula.