Reduce the Equation 5y+3 = 0 into intercept form and find its intercept on the axes.................

Reduce the Equation 5y+3 = 0 into intercept form and  find its intercept on the axes.................

Sol  : 



We have                        5y + 3 = 0

Or                                           5y = -3


Or                                       5y/3 = -3/3

Or                                    y/3/5   =  -1

Or                                    -y/3/5 = 1



Therefore      Intercepts on the axes are 0 and -3/5.............



Keywords  :  Geeks Networks, coordinate geometry, mathsmania, NCERT solved answers, slope of line, solved answers of mathematics of 11th class, Straight Lines,

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Reduce the Equation 3x+2y-12=0 into intercept form and find its intercepts on the axes...........

Reduce the Equation 3x+2y-12=0 into intercept form and find its intercepts on the axes...........

Sol  :

here                                 3x+2y-12=0

Or                                          3x+2y = 12

Dividing by 12    we get,

                                               x/4 + y/6 = 1

Therefore                         Intercepts on the Axes are  4 and 6............


Keywords   :   coordinate geometry, Geeks Networks, NCERT solved answers, mathsmania, solved answers of mathematics of 11th class, slope of line, Straight Lines,

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Reduce the Equation 6x+2y-5=0 into slope-intercept form and find its slope and intercept........

Reduce the Equation 6x+2y-5=0 into slope-intercept form and find its slope and intercept........

Sol   :

            Here Equation is
                                      6x+2y-5=0

Or                                           2y = -6x+5

Or                                             y = -6/2x+5/2

Or                                             y = -3x+5/2

Therefore                  Slope = -3      and Intercept = 5/2





Keywords   :   coordinate geometry, Geeks Networks, mathsmania, NCERT solved answers, solved answers of mathematics of 11th class, Straight Lines,

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Reduce the equation x+7y = 0 into slope intercept form and find its slope and the intercept.....

Reduce the equation x+7y = 0 into slope intercept form and find its slope and the intercept.....

Sol : 

             x + 7y = 0

Or        7y = -x

Or          y = -1/7x + 0

Therefore         Slope = -1/7      and     Intercept = 0







Keywords   :   CBSE, coordinate geometry, Geeks Networks, NCERT solved answers, solved answers of mathematics of 11th class, mathsmania, Straight Lines,

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Solved Question of Ex.10.2 of Class 11th............Q.No..20

Solved Question of Ex.10.2 of Class 11th............

Q.No..20......................

keywords : CBSE, coordinate geometry, Geeks Networks, NCERT solved answers, slope of line, solved answers of mathematics of 11th class, Straight Lines, 

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Q.No. 18 of Ex. 10.2 of Class 11th

Q.No. 18 of Ex. 10.2 of Class 11th.............

Sol : 

 Keywords : CBSE, coordinate geometry, Geeks Networks, mathsmania, NCERT solved answers, slope of line, solved answers of mathematics of 11th class, Straight Lines,

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The perpendicular from the origin to a line meet at the point (-2,9), find the equation of the line.

The perpendicular from the origin to a line meet at the point (-2,9), find the equation of the line.

Sol: 

 

Keywords : Area of Triangle, CBSE, coordinate geometry, Geeks Networks, NCERT solved answers, slope of line, solved answers of mathematics of 12th class, Straight Lines, 

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Find the equations of the lines passing through the point (2,2),such that the sum of their intercepts on the axes is 9.

Q.No.13 of Exercise 10.2 of Class 11th

Find the equations of the lines passing through the point (2,2),such that the sum of their intercepts on the axes is 9.

Sol :

keywords : CBSE, Calculus, Area of Triangle, base, Geeks Networks, integrations, NCERT solved answers, slope of line, Software, Straight Lines, solved answers of mathematics of 11th class, solved answers of mathematics of 12th class,

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Find the equation of a line that cuts off equal intercepts on the co-ordinate axes and passes through (2,3).

Q.No 12 of Exercise 10.2 of Class 11th
Find the equation of a line that cuts off equal intercepts on the co-ordinate axes and passes through (2,3).

Sol :

Keywords :   CBSE, Geeks Networks,  solved answers of mathematics of 11th class, Straight Lines, NCERT

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A line perpendicular to the line segment joining the points(1,0) and (2,3) divides it in ratio 1:n. Find the equation of the line.

Q.No. 11 of Ex. 10.2 of Class 11th
A line perpendicular to the line segment joining the points(1,0) and (2,3) divides it in ratio 1:n. Find the equation of the line.

Sol :

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Find the Equation of the line passing through (-3,5) and perpendicular to the line through the points (2,5) and (-3,6).

Ex 10.2 of Class 11th

Q. No. 10
Find the Equation of the line passing through (-3,5) and perpendicular to the line through the points (2,5) and (-3,6).

Sol : 

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Find the Equation of a line whose perpendicular distance from the origin is 5 units and the angle made by the perpendicular with positive x-axis is 30.

Ex 10.2

Q. No. 8
Find the Equation of a line whose perpendicular distance from the origin is 5 units and  the angle made by the perpendicular with positive x-axis is 30.

Sol :

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Find the Equation of the line AB when it meets x-axis at (-3,0) with slope = -2

Find the Equation of the line AB when it meets x-axis at (-3,0) with slope = -2


Sol :

Here,

                m = -2

                x₁ = -3  and y₁ = 0

Therefore           Equation of the line AB:

                                Y-0 = -2(x+3)

Or                           Y = -2x-3

Or                           2x+y+6 = 0

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Find the Equation of the line which is passing through the point (0,0) with slope m.

Sol :

Here

              X₁ = 0 and y₁ = 0

             Slope = m

Therefore,           Equation of the line is :

                            

                             (y-0) = m(x-0)

Or                          y = mx

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Find the Equation of the line which is passing through (-4,3) with slope 1/2

Find the Equation of the line which is passing through (-4,3) with slope 1/2


Sol :

We know that Equation of line will be (y-y₁) = m(x-x₁) when slope of line and a point is given.

Here 
    

x₁ = -4 ,  y₁ = 3  and  m = 1/2

 Therefore,  The Required equation of the line is 

                      (y-3) = 1/2(x+4).

Or,                2y-6 = x+4

Or,         x-2y+10 = 0

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Write the equations for x and y-axis.

Write the equations for x and y-axis.

Sol :

Equation of x-axis is y = 0.

and

Equation of y-axis is x = 0.

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The Slope of a line is double of the slope of another line. If tangent of the angle between them is 1/3, find the slopes of the line.

Q.No. 11 of Exercise 10.1 of Class 11th

The angle between x-axis and the line joining the points A(3,-1) and (4,-2).

Sol :

Let m₁ and m_{2 be the slopes of the two lines.}

_{Given that}        m₁ = 2m₂

 
Let x be the angle between the lines.

We know that,         tanx = m₁ – m₂/1+m₁m₂

                

_{Therefore,               1/3   =}   m₁ – m₂/1+m₁m₂

_Putting       m₁ = 2m_2,

_{Therefore,              1/3  =} 2m₂ – m₂/1+2m₂m₂ 

                                 

      _{Or                          1/3   =}   m₂/1+2m₂²

       ^Or                          3m₂  = 1+2m₂²

        Or                2m₂²-3m₂+1 = 0

       Or          2m₂²-2m₂- m₂+1 = 0

      Or        2m₂(m₂-1)-1(m₂-1) = 0

      Or              (2m₂-1)( m₂-1) = 0

Therefore,        m_{2 = 1/2      OR}          m_{2 = 1}   

Now,

         For   m_{2 = 1/2}         m_{1 = 1}

_{and   For}     m_{2 = 1}          m_{1= 2}

_{Hence, Slope of these lines are  1, 1/2 or 2,1.} 

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