The two adjacent sides of a parallelogram are 5 cm and 4 cm respectively, and if the respective diagonal is 7 cm then find the area of the parallelogram?
Sol :
We know that
Required Area = 2 Sqrt{s(s-a)(s-b)(s-D)
Where S = a+b+D/2
= 5+4+7/2 = 8
Now Area = 2 sqrt{8(8-5)(8-4)(8-7)}
= 2 sqrt{8x3x4x1}
= 8 sqrt (6)
Sqrt = Square root
Keywords : CBSE, Geeks Networks, NCERT solved answers, solved answers of mathematics of 11th class,
Sol :
We know that
Required Area = 2 Sqrt{s(s-a)(s-b)(s-D)
Where S = a+b+D/2
= 5+4+7/2 = 8
Now Area = 2 sqrt{8(8-5)(8-4)(8-7)}
= 2 sqrt{8x3x4x1}
= 8 sqrt (6)
Sqrt = Square root
Keywords : CBSE, Geeks Networks, NCERT solved answers, solved answers of mathematics of 11th class,
0 comments:
Post a Comment