Q.No. 13 of Exercise 10.1 of Class 11th
If three points (h.0),(a,b) and (0,k) lie on line, show that a/h+b/k=1.
Sol :
Let,
The given points are A(h,0), B(a,b), C(0,k)
These points lie on the same line
Therefore,
Slope of AB = Slope of BC.
Here,
Slope of AB = b-0/a-h = b/a-h
Slope of BC = k-b/0-a = k-b/-a
Now
b/a-h = k-b/-a
Or -ab = (a-h)(k-b) [By Cross Multiplication]
Or -ab = ak-ab-hk+bh
Or 0 = ak-hk+bh
Or ak+bh = hk
Dividing both side by hk, we get
ak/hk + bh/hk = hk/hk
Or a/h + b/k = 1
If three points (h.0),(a,b) and (0,k) lie on line, show that a/h+b/k=1.
Let,
The given points are A(h,0), B(a,b), C(0,k)
These points lie on the same line
Therefore,
Slope of AB = Slope of BC.
Here,
Slope of AB = b-0/a-h = b/a-h
Slope of BC = k-b/0-a = k-b/-a
Now
b/a-h = k-b/-a
Or -ab = (a-h)(k-b) [By Cross Multiplication]
Or -ab = ak-ab-hk+bh
Or 0 = ak-hk+bh
Or ak+bh = hk
Dividing both side by hk, we get
ak/hk + bh/hk = hk/hk
Or a/h + b/k = 1
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